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Forces perpendicular to the displacement will be negligible because it work will only result too. 2. T 8 Derive the equation: W=wall-coos Dividing both equations: F=wetland where DSL=Old W=willingness W=wall(1-coos) -cods) 3. Plot the force F against the horizontal displacement x of the mass m then interpret the graph. The graph shows a direct and proportional relationship between the force and horizontal displacement. This is because, the force is directly proportional to the change in the angle of the object, and is also directly proportional to the rational displacement.

Therefore, as the displacement increases, the force will also increase. INTERPRETATION OF RESULTS On the first part of the experiment, a fan cart was used to show how force, work and power are related. It is observed that as the displacement increases, the work done by the fan cart also increases. By graphing, the work-displacement relation is linear. It has a slope of 0. 49 which is equal to force. (Not exactly 0. 49 because of some errors made during the measurement of the displacement). Figure 1: displacement-work graph for part 1 Power can be obtained using the work we had obtained.

Through its definition, power can be expressed as work per change in time. We should expect that the power is constant. It is because the fan cart is moving at a constant velocity and a constant force. For the second part, work is calculated on a curved path. Even for varying force and even for a curve path of motion, work-energy theorem is still applicable. By applying the law of conservation of mechanical energy, we could say that it follows the general interpretation this scenario even at varying direction (circular tat) is: TIE+Hoot=TEE where TIE is the total energy at Pl and TEE for UP, respectively.

TIE=EKE+PIE, similarly, TEE=EKE+PEE EKE +Hoot=EKE+PEE 0+might+Hoot=O+MGM Hoot=mega So, the total work done is actually equal to the gravitational potential energy. In the result, it is obviously seen that high percentage error is calculated. It is because there are many ways of committing a mistake in this part. Some of these factors are measuring the angle and the height and applying an extremely “horizontal force” The y-component of the tension doesn’t affect work done by force. It only changes the direction of the mass. The Ah-PEg graph is linear which has an equation off=4. Xx which means that the slope of the graph is almost the same as the mass of the object. As height of object increases, higher potential energy it restores. With each unit increase in height, work is done against force of gravity and equal amount of energy is stored. Potential energy of an object at the earth’s surface is not zero. When a body moves away from the earth (i. E increases its vertical distance from the surface of the earth), it has to do work against the gravitational field which pulls he body towards the earth.

This work done by the body against the gravitational field is stored as the potential energy of the body. Therefore as we go higher from the surface of the earth the potential energy of our body increases. Our graph of Ah-Work is really different from the ideal graph. To partially correct this huge error, linear trend line is used. The slope of this (4. 67) is somewhat similar to the original equation (4. 9). The total force we had applied in the object is transformed into potential energy as it stops at a higher height.

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