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No effervescence is produced . No changes occur No sound is heard . The glowing splinter is extinguished as the glowing splinter is inserted . 3 Pulped liver High density of effervescence is produced vigorously . Pop sound is heard . The glowing splinter is ignited with spark and violent flame and extinguished within 18 second . When the glowing splinter is pulled out , it rekindled. 4 Potato cubes No pop sound is heard . The glowing splinter is ignited gently and extinguished within 3 second . 5 Manganese dioxide (untreated) Least effervescence is produced . The test tube is warm extinguished within 20 second .

When the glowing splinter is pulled out , it rekindled. 6 Boiled manganese dioxide (cooled after heating) extinguished within 7 second . When the glowing splinter is pulled out , it rekindled . Discussion The equation involved in this experiment is decomposition of hydrogen peroxide . H2O( liquid) – H2O(liquid) + 02 ( gas ) Peroxides ( micro-bodies ) are cytoplasm organelles involved in metabolism of hydrogen peroxide , H2O . It widely presence in most animal and plant cell . Therefore , peroxides can be found few in number in chicken liver and potato bubs .

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The function of peroxides is generating enzyme ( catalane ) which needed to decompose hydrogen peroxide . But this reaction need at least one molecule of hydrogen peroxide to generate the reaction . The reason of pulping the liver is to increase the total surface area over volume to allow more peroxides react with hydrogen peroxide to produce high catalane reaction ( effervescence ) . The optimal temperature of enzyme to function is maximum rate is ICC ( human body temperature ) , but it still can function below this temperature as long it it’d exceed ICC that cause the denature of enzyme .

So , when the liver is boiled under temperature of ICC , the hydrogen bond , disulphide bond , ionic bond will break down and protein structure is become uncoiled and unfolded. This lead to the AD shape of enzyme is changed . The active side of the enzyme is also changed and cannot be binned by the substrate ( hydrogen peroxide ) . This causes no reaction occur , no effervescence is produced . The differences between the reactions with fresh liver and with fresh potato cubes is due to the amount of peroxide and shape . The amount of peroxide is higher amount in fresh liver than fresh potato cubes .

Therefore , in fresh liver , there are more amount of catalane is produced to break down the hydrogen peroxide bond than potato cubes . Beside for that , the shape of fresh liver is flat but potato cubes is cube shape . This lead to fresh liver produce higher total surface area than potato cubes . The higher the total surface area of fresh liver than potato cubes result higher reaction between peroxide and hydrogen peroxide . This lead to time taken in fresh liver for peroxide to reduce catalane to decompose hydrogen peroxide in shorter than fresh potato .

Therefore , the higher amount of peroxide also lead to higher amount of active site to be binned by substrate The differences between the effects on the reaction of boiling the liver and heating the manganese dioxide is due to manganese dioxide is an inorganic catalyst thus it does not denature after boiling like liver . Manganese dioxide is not a protein and has a simple shape that does not sensitive to temperature ( at least above 5th ) like liver does .

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